Your choice (benzoic acid) is 

(It is also correct if you choose to separate 4-bromoaniline first.)

Let's separate benzoic acid.

If you want to make only benzoic acid* water soluble, which aqueous solution will you add?

dilute aqueous HCl (a strong acid)
dilute aqueous NaOH (a weak base)

Click ADD to add the selected solution to the separatory funnel